試題1

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試題2

（ ）  不能保證求得 0-1 背包問題的最優(yōu)解。
A、分支限界法
B、貪心算法
C、回溯法
D、動態(tài)規(guī)劃策略

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試題3

一個類是  （1）。在定義類時，將屬性聲明為private的目的是  （2）。
（1） A．一組對象的封裝
B．表示一組對象的層次關系
C．一組對象的實例
D．一組對象的抽象定義
（2）A．實現(xiàn)數(shù)據隱藏，以免意外更改
B．操作符重載
C．實現(xiàn)屬性值不可更改
D．實現(xiàn)屬性值對類的所有對象共享

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試題4

兩個同符號的數(shù)相加或異符號的數(shù)相減，所得結果的符號位SF和進位標志CF進（ ）運算為1時，表示運算的結果產生溢出。
A、與
B、或
C、與非
D、異或

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試題5

In a world where it seems we already have too much to do, and too many things to think about, it seems the last thing we need is something new that we have to learn.
But use cases do solve a problem with requirements: with （1 ） declarative requirements it's hard to describle steps and sequences of events.
Use cases, stated simply, allow description of sequences of events that, taken together, lead to a system doing something useful. As simple as this sounds, this is important. When confronted only with a pile of requiements, it's often（2 ）to make sense of what the authors of the  requirements really wanted the system to do. In the preceding example, use cases reduce the ambiguity of the requirements by specifying exactly when and under what conditions certain behavior occurs; as such, the sequence of the behaviors can be regarded as a requirement. Use cases are particularly well suited to capture approaches. Although this may sound simple, the fact is that (3 ) requirement capture approaches, with their emphasis on declarative requirements and "shall" statements, completely fail to capture fail to capture the (4 ) of the system's behavior. Use cases are a simple yet powerful way to express the behavior of the system in way that all stakeholders can easily understand.
But, like anything, use cases come with their own problems, and as useful as they are, they can be (5 ). The result is something that is as bad, if not worse, that the original problem. Therein it's important to utilize use cases effectively without creating a greater problem than the one you started with.
（1）A.plenty
B.loose
C.extra
D.strict
（2）A.impossible
B.possible
C.sensible
D.practical
（3）A.modern
B.conventional
C.different
D.formal
（4）A.statics
B.nature
C.dynamics
D.originals
（5）A.misapplied
B.applied
C.used
D.powerful

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試題6

在面向對象軟件開發(fā)過程中，采用設計模式（ ）。
A、允許在非面向對象程序設計語言中使用面向對象的概念  
B、以復用成功的設計和體系結構 
C、以減少設計過程創(chuàng)建的類的個數(shù)  
D、以保證程序的運行速度達到最優(yōu)值

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試題7

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試題8

設某語言的語法規(guī)則用上下文無關文法 G=(N,T,P,S)表示，其中 N 是非終結符號的集合，T是終結符號的集合，P 是產生式集合，S 是開始符號，令 V=N∪T，那么符合該語言的句子是（ ） 。
A、從 S 出發(fā)推導的、僅包含 T 中符號的符號串
B、從 N 中符號出發(fā)推導的、僅包含 T 中符號的符號串
C、從 S 出發(fā)推導的、包含 V 中符號的符號串
D、從 N 中符號出發(fā)推導的、包含 V 中符號的符號串

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試題9

冗余技術通常分為 4 類，其中  （ ）  按照工作方法可以分為靜態(tài)、動態(tài)和混合冗余。
A、時間冗余
B、信息冗余
C、結構冗余
D、冗余附加技術

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試題10

模塊A直接訪問模塊B的內部數(shù)據，則模塊A和模塊B的耦合類型為（）。
A．數(shù)據耦合
B．標記耦合
C．公共耦合
D．內容耦合

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